sábado, 9 de junio de 2012

Trabajo Practico nº2 Ejercicio 4


                                
                               Calcular la resistencia equivalente

a)

https://blogger.googleusercontent.com/img/b/R29vZ2xl/AVvXsEhNodB606zAPrJUmXPe501W35Fh0D2_9VSlSgtLijcUiD68wm48tx7hD4utGfy7jE-YjNGHS0DiJt0B8R9-y7IOAOvtG-nUKo3E4VFVlUF667brfQMxUyN7KgEX1cHNmgoA1xvdK2P3KA4/s1600/4-a.jpg

Re= R1 + R2= 100Ω + 50Ω= 150Ω
 
b)




https://blogger.googleusercontent.com/img/b/R29vZ2xl/AVvXsEhsGontm4QGawsNPkOoCHqk5USP5VNLaIbTbqe-OHwl5-GY6JZO0BMXzN9O_wpInFZjQDym1pvup-6X_AfW0hF_P7PGkePULAEwgPGNmJ-2z3m1BlI-e9C3GqQlKIY3yEDxU10xIhmr4nE/s1600/4-b.jpg

Re= R1 + R2 + R3= 500Ω + 700Ω + 350Ω= 1550Ω

 c)
https://blogger.googleusercontent.com/img/b/R29vZ2xl/AVvXsEhNZZUYrLyLJSvUwt6K0CyF7OBUDgwVjzmHb4cZ-c3k5Fhrqa8hyphenhyphenftsF44avTToaxMikzGVLxps9BWQLlP27OJA01ALZ-H8fyHLSG1u6CLp_2LxHCg1mniNMkpf102Ip9DwjNhqFZ5jloQ/s1600/4-c.jpg  
Re= (250Ω x 100Ω) / (250Ω + 100Ω)= 25000Ω^2 / 350Ω= 71,42Ω
d)

 https://blogger.googleusercontent.com/img/b/R29vZ2xl/AVvXsEi9-kEX16SnL7CNaTrwhx98P1ly-9dKqSyFfp9RvBkXM-w6XwtzdK1nNGlkHlmxswAK4dQWp9gyAfxlJ5lBTU466hySzaTwA3k1qiBxJ90K0QSGFQzYJsSq6cs-Andi-vSTQ_1YkYei7Z8/s1600/4-d.jpg 
 
Re= (300Ω x 300Ω) / (300Ω + 300Ω)= 90000Ω^2 / 600Ω= 150Ω

e)
https://blogger.googleusercontent.com/img/b/R29vZ2xl/AVvXsEifUf8ixfaaEIzy2OKM8V_EI8dT8GbN_fKraAjOm2bI_ihtiEWPH349VRNs1tvhDqfVGlIyyQ-IYbnyK9unkHfgKvIFxsX7eNECjghWw1f5bmWgJWaMoLUgBmr0MmIdM26jfO3AIZtqW6c/s1600/4-e.jpg 

 Rx= (200Ω x 100Ω) / (200Ω + 100Ω)= 20000Ω^2 / 300Ω=       66,6666667Ω
Rt= (50Ω x 6,6666667Ω) / (50Ω + 6,6666667Ω)= 3333,33334Ω^2 / 116,6666667Ω= 28,5741Ω




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